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ACT Problem PowerPoint PPT Presentation


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ACT Problem. (6a – 12) – (4a + 4) = ? 2(a+2) 2(a+4) 2(a-2) 2(a-4) 2(a-8). ACT Problem. (6a – 12) – (4a + 4) = ? Suppose a = 1. (6(1)-12) – (4(1) + 4) (6-12) – (4+4) -6 – 8 -14. ACT Problem. (6a – 12) – (4a + 4) = ? Our answer was a -14 If a = 1, then 2(a+2) = 2(3) = 6

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ACT Problem

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Act problem

ACT Problem

(6a – 12) – (4a + 4) = ?

  • 2(a+2)

  • 2(a+4)

  • 2(a-2)

  • 2(a-4)

  • 2(a-8)


Act problem1

ACT Problem

(6a – 12) – (4a + 4) = ?

Suppose a = 1.

(6(1)-12) – (4(1) + 4)

(6-12) – (4+4)

-6 – 8

-14


Act problem2

ACT Problem

(6a – 12) – (4a + 4) = ?

Our answer was a -14

If a = 1, then

  • 2(a+2) = 2(3) = 6

  • 2(a+4) = 2(5) = 10

  • 2(a-2) = 2(-1) = -2

  • 2(a-4) = 2(-3) = -6

  • 2(a-8) = 2(-7) = -14


Vertical angles and transversals

Vertical Angles and Transversals


Naming an angle

Naming an Angle

4 Ways

By the points that

Compose it:

<NMO or <OMN

By the vertex (or pivot

point of the angle):

<M

Or the number associated with it: <1


Vertical lines

Vertical Lines

Vertical lines are

opposite each other.

They are always equal.


Transversal of parallel lines

Transversal of Parallel Lines

Angles

1=3=5=7

Angles

2=4=6=8


Angles formed by a transversal

Angles Formed by a Transversal

Alternate exterior

Alternate interior


Angles formed by a transversal1

Angles Formed by a Transversal

Corresponding

Consecutive Interior


Solving for x

Solving for x

Set up the information you know and solve for x as you would in algebra:

2x + 4 + 38 = 90

2x + 42 = 90

-42 -42

2x = 48

2 2

x = 24

2x + 4


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