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Concentration of SolutePowerPoint Presentation

Concentration of Solute

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(

M

)

=

Molarity

liters of solution

Concentration of SoluteThe amount of solute in a solution is given by its concentration.

1.0 L of water was used to make 1.0 L of solution. Notice the water left over.

PROBLEM: Dissolve 5.00 g of NiCl the water left over.2•6 H2O in enough water to make 250 mL of solution. Calculate the Molarity.

Step 1: Calculate moles of NiCl2•6H2O

Step 2: Calculate Molarity

[NiCl2•6 H2O] = 0.0841 M

USING MOLARITY the water left over.

What mass of oxalic acid, H2C2O4, is

required to make 250. mL of a 0.0500 M

solution?

Step 1: Change mL to L.

250 mL * 1L/1000mL = 0.250 L

Step 2: Calculate.

Moles = (0.0500 mol/L) (0.250 L) = 0.0125 moles

Step 3: Convert moles to grams.

(0.0125 mol)(90.00 g/mol) = 1.13 g

moles = M•V

Learning Check the water left over.

How many grams of NaOH are required to prepare 400. mL of 3.0 M NaOH solution?

1) 12 g

2) 37 g

3) 300 g

Concentration Units the water left over.

An IDEAL SOLUTION is one where the properties depend only on the concentration of solute.

Need conc. units to tell us the number of solute particles per solvent particle.

The unit “molarity” does not do this!

mol solute the water left over.

m of solution

=

kilograms solvent

Two Other Concentration UnitsMOLALITY, m

% by mass

grams solute

grams solution

% by mass =

Calculating Concentrations the water left over.

Dissolve 62.1 g (1.00 mol) of ethylene glycol in 250. g of H2O. Calculate molality and % by mass of ethylene glycol.

Calculating Concentrations the water left over.

Dissolve 62.1 g (1.00 mol) of ethylene glycol in 250. g of H2O. Calculate m & % of ethylene glycol (by mass).

Calculate molality

Calculate weight %

Learning Check the water left over.

A solution contains 15 g Na2CO3 and 235 g of H2O? What is the mass % of the solution?

1) 15% Na2CO3

2) 6.4% Na2CO3

3) 6.0% Na2CO3

Using mass % the water left over.

How many grams of NaCl are needed to prepare 250 g of a 10.0% (by mass) NaCl solution?

Try this molality problem the water left over.

- 25.0 g of NaCl is dissolved in 5000. mL of water. Find the molality (m) of the resulting solution.

m = mol solute / kg solvent

25 g NaCl 1 mol NaCl

58.5 g NaCl

= 0.427 mol NaCl

Since the density of water is 1 g/mL, 5000 mL = 5000 g, which is 5 kg

0.427 mol NaCl

5 kg water

= 0.0854 m salt water

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