Permutations and combinations
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MDM 4U: Mathematics of Data Management Unit: Counting and Probability By: Mr. Allison and Mr. Panchbhaya. Permutations and Combinations. Specific Expectations. Strand 2.1

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Permutations and Combinations

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Permutations and combinations

MDM 4U: Mathematics of Data Management

Unit: Counting and Probability

By: Mr. Allison and Mr. Panchbhaya

Permutations and Combinations


Specific expectations

Specific Expectations

  • Strand 2.1

  • Recognize the use of permutations and combinations as counting techniques with advantages over other counting techniques

  • Strand 2.2

  • Solve simple problems using techniques for counting permutations and combinations, where all objects are distinct

Learning Goals

  • Make connections between, and learn to calculate various permutations and combinations

  • Learn to behave in class


Agenda of the day

Agenda of the Day

  • Probability Video

  • Review

  • Worksheet

  • Game show Activity


How many combinations would it take for the tire to attach itself back to the car

How many combinations would it take for the tire to attach itself back to the car?


Real life examples

Real Life Examples

  • Video game designers

    • to assign appropriate scoring values

  • Engineering

    • new products tested rigorously to determine how well they work

  • Allotting numbers for:

    • Credit card numbers

    • Cell phone numbers

    • Car plate numbers

    • Lottery


Factorials

Factorials

  • The product of all positive integers less than equal or equal to n

    n! = n x (n – 1) x (n – 2) x … x 2 x 1

    5! =5 x 4 x 3 x 2 x 1 = 120


Permutations

Permutations

  • Ordered arrangement of objects selected from a set

  • Ordered arrangement containing a identical objects of one kind is


Combinations

Combinations

  • Collection of chosen objects for which order does not matter


Permutations and combinations

Speed Round: The sports apparel store at the mall is having a sale. Each customer may choose exactly two items from the list, and purchase them both. The trick is that each 2-item special must have two different items (for example, they may not purchase two T-shirts at the same time). What are all the different combinations that can be made by choosing exactly two items?


Permutations and combinations

15 combinations are possible


Q how many combinations are made if you were purchasing three items instead of two

Q – How many combinations are made if you were purchasingthree items instead of two?


1 a club of 15 members choose a president a secretary and a treasurer in

1. A club of 15 members choose a president, a secretary, and a treasurer in

  • 455 ways

  • 6 ways

  • 2730 ways


2 the number of debate teams formed of 6 students out of 10 is

2. The number of debate teams formed of 6 students out of 10 is:

  • 151200

  • 210

  • 720


Permutations and combinations

3. A student has to answer 6 questions out of 12 in an exam. The first two questions are obligatory. The student has:

  • 5040

  • 210

  • 720


Permutations and combinations

4. From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done.

  • 564

  • 645

  • 735

  • 756

  • None of the above


Permutations and combinations

5. In how many different ways can the letters of the word “LEADING” be arranged in such a way that the vowels

  • 360

  • 480

  • 720

  • 5040

  • None of the above


Permutations and combinations

6. How many permutations of 4 different letters are there, chosen from the twenty six letters of the alphabet (repetition is not allowed)?


Answer

Answer

The number of permutations of 4 digits chosen from 26 is 26P4 = 26 × 25 × 24 × 23 = 358,800


How many paths are there to the top of the board

How many paths are there to the top of the board?


Answer1

Answer


How many 4 digit numbers can be made using 0 7 with no repeated digits allowed

How many 4 digit numbers can be made using 0-7 with no repeated digits allowed?

  • 5040

  • 4536

  • 2688

  • 1470


Answer2

Answer

  • = 7x7x6x5 = 1470

  • First digit of a number can not be ‘0’


Permutations and combinations

No postal code in Canada can begin with the letters D,F,I,O,Q,U, but repeated letters are allowed and any digit is allowed. How many postal codes are possible in Canada?

  • 11,657,890

  • 13,520,000

  • 14,280,000

  • 12,240,000


Answer3

Answer

  • = 20x10x26x10x26x10 = 13,520,000

  • 20 choices for the first letter (26 - 6 that cannot be chosen. 10 choices for the digit (0-9).

  • 26 choices for the 3 position (2nd letter)

  • then 10 choice for the 4th position

  • Then 26 and 10 since you can again repeat numbers and letters.


Using digits 0 9 how many 4 digit numbers are evenly divisible by 5 with repeated digits allowed

Using digits 0 – 9, how many 4 digit numbers are evenly divisible by 5 with repeated digits allowed?

  • 1400

  • 1600

  • 1800

  • 1500


Answer4

Answer

  • 9 × 10 × 10 × 2 = 1800

  • First # can’t be ‘0’

  • Last # has to be ‘5’ or ‘0’


How many ways can you arrange the letters in the word redcoats if it must start with a vowel

How many ways can you arrange the letters in the word REDCOATS if it must start with a vowel

  • 15,120

  • 14,840

  • 15,620

  • 40,320


Answer5

Answer

  • 3* × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 15,120

  • EOA are your 3 choices


Permutations and combinations

How many groups of 3 toys can a child choose to take on a vacation from a toy box containing 11 toys?

  • 990

  • 1331

  • 165

  • 286


Answer6

Answer

  • C(11,3) 165


If you have a standard deck of cards how many different hands exists of 5 cards

If you have a standard deck of cards how many different hands exists of 5 cards

  • 2,598,960

  • 3,819,816

  • 270,725

  • 311,875,200


Answer7

Answer

  • C(52,5)


Permutations and combinations

The game of euchre uses only 24 cards from a standard deck. How many different 5 card euchre hands are possible?

  • 7,962,624

  • 42,504

  • 5,100,480

  • 98,280


Answer8

Answer

  • C(24,5) 42,504


Solve for n 3 n p 4 n 1 p 5

Solve for n 3(nP4) =n-1P5

  • 8

  • 10

  • 2

  • 5


Answer9

Answer


How many ways can 3 girls and three boys sit in a row if boys and girls must alternate

How many ways can 3 girls and three boys sit in a row if boys and girls must alternate?


Answer10

Answer

  • = 3! x 3! + 3! x 3!

  • = 72


Permutations and combinations

Laura has ‘lost’ Jordan’s phone number. All she can remember is that it did not contain a0 or 1 in the first three digits. How many 7 digit #’s are possible


Answer11

Answer

  • = 8 x 8 x 8 x 10 x 10 x 10 x 10

  • = 5,120,000


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