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OBJECTIVE. REVISION MOD 3. G. Check the side of the slide to see what level you are working at!. F. E. D. C. B. A. A*. INTEGERS. INTEGER is a whole number. HCF / LCM simple numbers – C HCF / LCM complex or more than two numbers – B Recognise prime numbers – C

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Objective

OBJECTIVE

REVISION MOD 3


Check the side of the slide to see what level you are working at

G

Check the side of the slide to see what level you are working at!

F

E

D

C

B

A

A*


Integers
INTEGERS

  • INTEGER is a whole number.

  • HCF / LCM simple numbers – C

  • HCF / LCM complex or more than two numbers – B

  • Recognise prime numbers – C

  • Write a number as product of its prime numbers – C

  • Find the reciprocal of a number - C


Multiples
Multiples

G

  • These are all of the integers that appear in your number’s times table!

  • 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36.

  • 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84


Factors
Factors

G

  • These are all of the integers that will divide into your number and leave no remainder!

  • They are usually listed in pairs!

    e.g. the factors of 36 are:

    1 & 36

    2 & 18

    3 & 12

    4 & 9

    6 & 6


Prime numbers prime factors
Prime Numbers & Prime Factors

  • APRIME NUMBERhasTWO DIFFERENT FACTORS

    1 & ITSELF.

    The prime numbers less than 30 are ….

    2, 3, 5, 7, 11, 13, 17, 19, 23, 29

  • APRIME FACTOR, is a factor that is also a prime number.

    e.g. factors of12are1, 2 ,3 ,4 , 6 & 12of these2 & 3are prime factors.

    12can be written as a product of prime factors…

    12 = 2 x 2 x 3 in its INDEX FORM = 22 x 3

C


Highest common factor
Highest common Factor

  • Thehighest common factor (HCF)of two numbers, is the largest factor common to both.

    e.g.factors of 18 are 1,2,3,6,9,18

    factors of 30 are 1,2,3,5,6,10,15,30

    The highest factor common to both numbers is 6.

    We use HCF’s when cancelling fractions!!!

C


Lowest common multiple
Lowest Common Multiple

  • The Lowest Common Multiple (LCM) of two numbers, is the smallest number that appears in both time tables.

  • The example below is for the 9 & 15 times table…..

    e.g. the multiples of 9 are 9,18,27,36,45,54,63,….

    the multiples of 15 are 15,30,45,60,…

    45 is the lowest common multiple of each sequence of numbers

C


Prime factor product trees
Prime factor product trees

  • Products of prime numbers can be written as “trees”.

180

2 x 2 x 3 x 3 x 5 = 180

or; in INDEX FORM

22 x 32 x 5 = 180

90

x

2

45

x

C

2

15

3

x

5

x

x

3

x

x

x


Hcf and lcm
HCF and LCM

  • We can use prime factors to find the HCF and LCM…

    e.g. 504 = 2 x 2 x 2 x 3 x 3 x 7

    700 = 2 x 2 x 5 x 5 x 7

    HCF is 2 x 2 x 7 = 28

    LCM is 2 x 2 x 2 x 3 x 3 x 5 x 5 x 7 = 12600

    504 = 23 x 32 x 7

    700 = 22 x 52 x 7

    HCF is 22 x 7

    LCM is 23 x 32 x 52 x 7

B

This is what’s left from BOTH numbers

when you take out the

HCF


Consecutive numbers
Consecutive Numbers

  • A set of 5 consecutive numbers will increase by 5 each time, or are divisible by 5.

    e.g. 1+2+3+4+5 = 15

    2+3+4+5+6 = 20

    If n = starting number, then the next is (n+1), etc .

    n + (n+1) + (n+2) + (n+3) + (n+4) = 5n +10

    = 5(n+2)

C

Thus5 is always factor of a series of five

consecutive numbers


Indices
INDICES

  • INDEXis another word forPOWER.

  • Recall integer squares / square roots to 15 –D

  • Recall integer cube / cube roots to 5 –D

  • Use index laws for positive powers –C

  • Use index laws for negative powers –B

  • Use index laws with simple fractional powers –A

  • Use index laws with complex fractional powers –A*


Square numbers cube numbers
Square Numbers & Cube Numbers

  • ASQUARE NUMBERis a NUMBER x ITSELF.

    1 x 1 = 1, 2 x 2 = 4, 3 x 3 = 9, 4 x 4 = 16 and so on

    Remember the first 15 Square Numbers ….

    1,4,9,16,25,36,49,64,81,100,121,144,169,196,225.

  • ACUBE NUMBERis a NUMBER x ITSELF x ITSELF.

    1 x 1 x 1 = 1, 2 x 2 x 2 = 8, 3 x 3 x 3 = 27, and so on

    Remember the first 5 Cube Numbers ….

    1, 8, 27,64,125.

D


Square Root

TheNUMBERthat isSQUAREDto make9is3.

3is called theSQUARE ROOTof9and is written√9.

Remember the square roots as the reverse of the

square numbers.

SO √1,√4,√9,√16,√25,√36,√49,√64,√81,√100,√121,√144,√169,√196,√225

are the numbers from 1 to 15.

D


What are indices
What are Indices?

  • An Index is often referred to as a power

For example:

= 53

5 x 5 x 5

= 24

2 x 2 x 2 x 2

= 75

7 x 7 x 7x 7 x 7

5 is the INDEX

7 is the BASE NUMBER

75 & 24 are numbers in INDEX FORM


Rule 1 multiplication
Rule 1 : Multiplication

26 x 24

= 210

x

2x2x2x2x2x2

2x2x2x2

35 x 37

= 312

x

3x3x3x3x3

C

3x3x3x3x3x3x3

General Rule

am x an = am+n


Rule 2 division
Rule 2 : Division

44÷42

= 42

÷

4x4x4x4

4x4

26÷23

= 23

÷

2x2x2x2x2x2

C

2x2x2

General Rule

am÷ an = am-n


Rule 3 brackets
Rule 3 : Brackets

(26)2

= 26 x 26

= 212

(35)3

= 35 x 35 x 35

= 315

C

General Rule

(am)n = am x n


Rule 4 index of 0
Rule 4 : Index of 0

How could you get an answer of 30?

35÷ 35

= 35-5

= 30

30 =

1

C

General Rule

a0 = 1


Combining numbers
Combining numbers

x 2 x 2 x 2 x 2

5 x 5 x 5

= 53

x 24

We can not write this any more simply

Can ONLY do that if BASE NUMBERS are the same


Putting them together
Putting them together?

26 x 24

23

= 210

23

= 27

35 x 37

34

= 312

34

= 38

C

25 x 23

24 x 22

= 28

26

= 22


And a mixture
..and a mixture…

2a3 x 3a4

= 2 x 3 x a3 x a4

= 6a7

8a6÷ 4a4

= (8 ÷ 4) x (a6 ÷ a4)

= 2a2

2

2

8a6

4a4

C


Works with algebra too
Works with algebra too!

a6 x a4

= a10

b5 x b7

= b12

c5 x c3

c4

= c8

c4

= c4

C

a5 x a3

a4 x a6

= a8

a10

= a-2


Summary of rules
Summary of rules.

1. am x an = am+n

2. am÷ an = am-n

3. (am)n = am x n

4. a1 = a

5. a0 = 1


More rules rule 6 negative indices

1

2

General Rule

a-n =

1

an

More rules….. Rule 6 negative indices

25

32

24

16

23

8

22

4

21

2

20

1

2-1

2-2

B


Rule 7 fractional indices

General Rule

a = √a

n

Rule 7 – Fractional Indices

9 x 9 = 91 =9

From Rule 1 & 4

So 9 = √9

A


Rule 8 complex fractional indices
Rule 8 – Complex Fractional Indices

81= (4√81)³ = (3)³ = 27

General Rule

Treat the bottom as a fractional index so find

root, then use top part as a normal index.

A*


Standard index form
Standard Index Form

  • SIF is a way of writing big or small numbers using indices of 10.

  • Convert numbers to and from SIF – C

  • Use SIF in simple number problems – B

  • Use SIF in complex word problems – A


Why is this number very difficult to use?

999,999,999,999,999,999,999,999,999,999

Too big to read

Too large to comprehend

Too large for calculator

To get around using numbers this large, we use standard index form.


But it still not any easier to handle!?!

Look at this

100,000,000,000,000,000,000,000,000,000

At the very least we can describe it as 1 with 29 noughts.


How could we turn the number 800,000,000,000 into standard index form?

So, 800,000,000,000 = 8 x 1011 in standard index form

Let’s investigate!

Converting large numbers

We can break numbers into parts to make it easier,

e.g. 80 = 8 x 10 and 800 = 8 x 100

C

800,000,000,000 = 8 x 100,000,000,000

And 100, 000,000,000 = 1011


Standard form standard index form
Standard Form (Standard Index Form) index form?

5.3 x 10n

There will also be a power of 10

C

The first part of the number is between

1 and 10

But NOT 10 itself!!


The first number must be a value between index form?

1 and 10

One of the most important rules for writing numbers in standard index form is:

But NOT 10 itself!!

For example, 39 x 106 does have a value but it’s not written in standard index form.

The first number, 39, is greater than 10.

3.9 x 107 is standard index form.

C


Indices of ten
Indices of Ten index form?

Notice that the number of zeros

matches the index number

2

100

10

10

10

10

3

1,000

4

10,000

5

100,000


10 index form?

So, 45,000,000,000 = 4.5 x 1010

Quick method of converting numbers to standard form

For example,

Converting 45,000,000,000 to standard form

Place a decimal point after the first digit

4.5000000000

Count the number of digits after the decimal point.

C

This is our index number (our power of 10)


And numbers less than 1
And numbers less than 1? index form?

How can we convert 0.067 into standard index form?

0.067 = 6.7 x 0.01

0.01 = 10-2

C

0.067 = 6.7 x 10-2


And numbers less than 1? index form?

How can we convert 0.000213 into standard index form?

0.000213 = 2.13 x 0.0001

0.0001 = 10-4

C

0.000213 = 2.13 x 10-4


56 index form?

567

5678

56789

0.56

0.056

0.0056

Write the following in standard form.

0.00056

23

234

4585

4.6

0.78

0.053

0.00123

How to write a number in standard form.

Place the decimal point after the first non-zero digit then multiply or divide it by a power of 10 to give the same value.

= 5.6 x 10 = 5.6 x 101

= 5.67 x 100 = 5.67 x 102

= 5.678 x 1000 = 5.678 x 103

= 5.6789 x 10 000 = 5.6789 x 104

= 5.6  10 = 5.6 x 10-1

C

= 5.6  100 = 5.6 x 10-2

= 5.6  1000 = 5.6 x 10-3

= 5.6  10 000 = 5.6 x 10-4

2.3x 101

2.34x 102

4.585x 103

4.6x 100

7.8x 10-1

5.3x 10-2

1.23x 10-3


Examples: index form?

Exp/EE?

Calculate: 4.56 x 108x 3.7 x 105

+/-

Sharp

Standard Form on a Calculator

You need to use the exponential key (EXP or EE) on a calculator when doing calculations in standard form.

4.56

Exp

8

x

3.7

Exp

5

=

1.6872 x 1014

1.7 x 1014(2sig fig)

Calculate: 5.3 x 10-4 x 2.7 x 10-13

C

5.3

Exp

- 4

x

2.7

Exp

- 13

=

1.431 x 10-16

1.4 x 10-16 (2 sig fig)

Calculate: 3.79 x 1018 9.1 x 10-5

3.79

Exp

18

9.1

Exp

- 5

=

4.2 x 1022(2 sig fig)


Calculations using sif

Calculations Using SIF index form?

B


Multiply two numbers
Multiply two numbers index form?

4 x 1018 x 3 x 104

Numbers

Powers of 10

4 x 3

x 1018 x 104

ADD powers

= 12

x 1022

NOT Std Form!

B

= 1.2 x 101

x 1022

= 1.2 x 1023


Complex word problems involving SIF index form?

The mass of the Earth is approximately

6 000 000 000 000 000 000 000 000 kg. Write this number in standard form.

6.0 x 1024

The mass of Jupiter is approximately

2 390 000 000 000 000 000 000 000 000 kg. Write this number in standard form.

2.39 x 1027

A

How many times more massive is Jupiter than Earth?

398

2.39 x 1027 / 6.0 x 1024 =


Complex word problems involving SIF index form?

The mass of a uranium atom is approximately

0. 000 000 000 000 000 000 000 395 g.

Write this number in standard form.

3.95 x 10-22

The mass of a hydrogen atom is approximately

0. 000 000 000 000 000 000 000 001 67 g.

Write this number in standard form.

1.67 x 10-24

How many times heavier is uranium than hydrogen?

A

237

3.95 x 10-22/ 1.67 x 10-24 =


Complex word problems involving SIF index form?

Writing Answers in Decimal Form (Non-calculator)

Taking the distance to the moon is 2.45 x 105 miles and the average speed of a space ship as 5.0 x 103 mph, find the time taken for it to travel to the moon. Write your answer in decimal form.

D

245 000

S

49

hours

S =

so T =

=

=

T

5 000

D

A


Rounding to nearest integer (whole number). index form?G.Rounding to nearest 10 or 100. G.Rounding to given number of decimal places. F.Rounding to given number of significant figures. E.

Rounding.


Rounding to the nearest whole number
Rounding index form?to the nearest whole number

G

  • Is the arrow nearer to 6, 7 or 8?

  • If it is halfway between, then round UP

6 7 8


Rounding to the nearest 10
Rounding index form?to the nearest 10

G

  • Is the arrow nearer to 20, 30 or 40?

  • If it is halfway between, then round UP

20 30 40


Rounding to the nearest 100
Rounding index form?to the nearest 100

G

  • Is the arrow nearer to 400 or 500?

  • If it is halfway between, then round UP

400 500


Decimal places

Decimal Places index form?

F


Round the following number to 1dp
Round the following number to 1dp index form?

6.348

F

If this number is a 0, 1, 2, 3 or 4 we don’t have to do anything else and we have our answer.

Now look at the number immediately after where we stopped highlighting

Firstly, highlight the number to the first number after the decimal point

So we have 6.3

But is this the answer?


Round the following number to 1dp1
Round the following number to 1dp index form?

6.348 = 6.3 (1dp)

F


What if the red number was a 5 6 7 8 or 9
What if the red number was a 5, 6, 7, 8 or 9? index form?

Lets look at an example

F


Round the following number to 1dp2
Round the following number to 1dp index form?

9.2721

F

If this number is a 5, 6, 7, 8 or 9 we increase the last digit by one.

Now look at the number immediately after where we stopped highlighting

Firstly, highlight the number to the first number after the decimal point

So we have 9.2

But is this the answer?

So 9.2 becomes 9.3


Round the following number to 1dp3
Round the following number to 1dp index form?

9.2721 = 9.3 (1dp)

F


Round the following number to 2dp
Round the following number to 2dp index form?

If this number is a 0, 1, 2, 3 or 4 we don’t have to do anything else and we have our answer, but it is not, so we round up the number in the second decimal place to give us our answer.

7.456

F

Firstly, highlight the number to the second number after the decimal point

Now look at the number immediately after where we stopped highlighting

7.46


Round the following number to 2dp1
Round the following number to 2dp index form?

If this number is a 0, 1, 2, 3 or 4 we don’t have to do anything else. In this case it is so we have our answer highlighted.

3.992

F

Firstly, highlight the number to the second number after the decimal point

Now look at the number immediately after where we stopped highlighting

3.99


Round the following number to 1dp4
Round the following number to 1dp index form?

6.348 = 6.3 (1dp)

F


What if the red number was a 5 6 7 8 or 91
What if the red number was a 5, 6, 7, 8 or 9? index form?

Lets look at an example

F


Round the following number to 1dp5
Round the following number to 1dp index form?

9.2721

F

If this number is a 5, 6, 7, 8 or 9 we increase the last digit by one.

Now look at the number immediately after where we stopped highlighting

Firstly, highlight the number to the first number after the decimal point

So we have 9.2

But is this the answer?

So 9.2 becomes 9.3


Round the following number to 1dp6
Round the following number to 1dp index form?

9.2721 = 9.3 (1dp)

F


Decimal Places (Rounding) index form?

Numbers can be rounded to 1,2, 3 or more decimal places.

Rounding to 1 d.p

4 . 8 3 2 5

5 or bigger ?

5 or bigger ?

5 or bigger ?

4.8

4.8

4.9

F

4. 8 5 2 5

4. 8 4 2 5

No

No

Yes


For example if a case of wine containing 6 bottles costs £25 then you could price a single bottle by calculating £25  6 = £4.166666667. It would be pointless to write out all the numbers on your calculator display. Since we are dealing with money (pounds and pence) we only need 2 decimal places (2 d.p.) So it would be much better to write down £4.17.

Decimal Places

It is often necessary/convenient/sensible to give approximations to real life situations or as answers to certain calculations.

F


Rounding to £25 then you could price a single bottle by calculating 1 d.p

4 . 8 3 2 5

4. 8 5 2 5

4. 8 4 2 5

No

No

Yes

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

4.9

4.9

4.9

4.8

4.8

4.9

F

4. 8 6 2 5

4. 8 7 2 5

4. 8 9 2 5

Yes

Yes

Yes


0.29 £25 then you could price a single bottle by calculating

0.40

1.43

0.56

0.61

5.84

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

Rounding to 2 d.p

1. 4 2 6 1

5. 8 4 2 5

0. 6 0 8 3

F

No

Yes

Yes

0. 2 9 4 3

0. 5 5 5 0

0. 3 9 7 0

Yes

No

Yes


6.295 £25 then you could price a single bottle by calculating

0.400

1.426

5.401

0.608

5.843

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

5 or bigger ?

Rounding to 3 d.p

1. 4 2 6 1 8

5. 8 4 2 5 4

0. 6 0 8 3 4

F

Yes

No

No

6. 2 9 4 7 1

5. 4 0 0 9 7

0. 3 9 9 7 7

Yes

Yes

Yes


Take care
Take Care! £25 then you could price a single bottle by calculating

  • Round 3.48 to 1 d.p

F

3.5

  • Round 3.48 to the nearest whole number

3 (not 4)


Significant figures

Significant Figures £25 then you could price a single bottle by calculating

E


Example

Example £25 then you could price a single bottle by calculating

E

Round

235440

To 2 significant figures


23 5 440
23 £25 then you could price a single bottle by calculating 5440

Underline the 1st 2 digits

Now look at the next digit

E

If this is 5 or more then you must round up

The 3 is changed to a 4

240000

All other digits are changed to zero


2350 £25 then you could price a single bottle by calculating

2400

437900

440000

69723

70000

43490

43000

  • What are these numbers to 2 significant figures?

E


What about decimal numbers

What about decimal numbers? £25 then you could price a single bottle by calculating

E

For example:

Round

0.004367

to 2 significant figures


0 004367
0.004367 £25 then you could price a single bottle by calculating

Underline the 1st 2 digits which are not zero

Look at the next digit along

E

You change the 3 to a 4

If it is 5 or more you add 1 to the previous digit

0.0044

You can ignore any number after the 1st 2 digits which are not zeros


Round the following to 2 significant figures £25 then you could price a single bottle by calculating

0.05475

0.055

0.00475

0.0048

0. 45475

0.45

E


Significant figures1
Significant figures £25 then you could price a single bottle by calculating

  • When first identifying significant numbers, zeros at the beginning or end don’t usually count, but zeros ‘inside’ the number do.

  • Digits of a number kept in place by zeros where necessary.

  • The rounded answer should be a suitable reflection of the original number e.g.

    24,579 to 1 s.f could not possibly be 2

    24,579 to 1 s.f is 20,000

E


Write questions and answers in your books
Write questions and answers in your books? £25 then you could price a single bottle by calculating

49382.95 to 2 s.f. and1dp =

0.05961 to 1 s.f. and2dp =

374.582 to 3 s.f. and 1dp =

0.0009317 to 2 s.f. and 3dp =

E

49000 49383.0

0.06 0.06

375 374.6

0.00093 0.001


Objective1
Objective: £25 then you could price a single bottle by calculating

  • Share a quantity into a given ratio.C.

  • Find an unknown number that fits a given ratio.C.


Sharing a quantity into a given ratio £25 then you could price a single bottle by calculating

For example, share 36 into the ratio 2 : 7

First ADD the ratio 2 + 7 = 9

Second DIVIDE this answer into the quantity to be shared 36 ÷ 9 = 4

Third MULTIPLY the ratio by this answer 2 X 4 : 7 X 4

This is the answer 8 : 28

C


When sharing into a given ratio, the name to remember is: £25 then you could price a single bottle by calculating ADaM

A

D

M

and

+

÷

X

Share 32 into the the ratio 3 : 5

3 + 5 = 832÷ 8 = 4

3 X 4 = 12 : 5 X 4 = 20

Answer 12 : 20

C


Share these into the given ratio
Share these into the given ratio £25 then you could price a single bottle by calculating

C


Share these into the given ratio £25 then you could price a single bottle by calculating

C


Finding an unknown number that fits a given ratio
Finding an unknown number that fits a given ratio £25 then you could price a single bottle by calculating

Example – If the ratio of red beads black beads is 3 : 5, how many black beads will I need for 21 red beads?

Red : Black

3 : 5

21 : ?

C


First find the number that you multiply 3 by to get 21
First find the number that you multiply 3 by to get 21 £25 then you could price a single bottle by calculating

Red : Black

3 : 5

21 : ?

C

X 7


Red : Black £25 then you could price a single bottle by calculating

3 : 5

21 : 35

C

X 7

X 7


Another Example £25 then you could price a single bottle by calculating

Red : Black

2 : 7

12 : ?

2 X 6 is 12 so you

multiply 7 by 6 to get the ?

C

X 6


Red : Black £25 then you could price a single bottle by calculating

2: 7

12 : 42

X 6

C

X 6


Fractions
FRACTIONS £25 then you could price a single bottle by calculating

Top number is the NUMERATOR, bottom number is the

DENOMINATOR

Find equivalent fractions. F

Simplify a fraction to its lowest form.E

Add and subtract fractions with common denominator.D

Multiply and divide fractions.D

Add and subtract fractions with different denominator.C

Convert to and from fractions, decimals and percentages.D

Be able to convert a recurring decimal to a fraction.C


What makes a fraction

Part £25 then you could price a single bottle by calculating

NUmerator

Denominator

o

Whole

n

What makes a fraction?


Something we do with fractions find equivalent
Something we do with Fractions. £25 then you could price a single bottle by calculating find EQUIVALENT

F

ent

iv

EQU = AL

= 


Something we do with fractions simplify

= £25 then you could price a single bottle by calculating

=

=

Something we do with Fractions.SIMPLIFY

S

i

E

m

=

p

L

=

i

f

=

y


Adding fractions
Adding Fractions £25 then you could price a single bottle by calculating

+

D

=


Subtracting fractions
Subtracting Fractions £25 then you could price a single bottle by calculating

D


What happens if

1 £25 then you could price a single bottle by calculating

1

+

3

4

What Happens if

  • The two bottom numbers are different

C


Find lcm lowest common multiple
Find LCM (Lowest Common Multiple £25 then you could price a single bottle by calculating )

Find multiples of 3 and 4

X table shows the multiples of 3

3,6,9,12,15,18,21,……..

X table shows the multiples of 4

4,8,12,16,20,24,…………

C


7 £25 then you could price a single bottle by calculating

12

Change the denominators into 12

  • 3

    3

4

C


1/3 £25 then you could price a single bottle by calculating

1/4

+

+

= ?

C

=

+

3/12 + 4/12 = 7/12


Another example but taking away
Another example but £25 then you could price a single bottle by calculating TAKING AWAY

  • The two bottom numbers are different

C


Find lcm lowest common multiple1

2 £25 then you could price a single bottle by calculating

1

-

3

6

Find LCM (Lowest Common Multiple)

Find multiples of 3 and 6

X table shows the multiples of 3

3,6,……..

X table shows the multiples of 6

6,…………

C


2 £25 then you could price a single bottle by calculating

1

-

3

6

2

2

C


1/3 £25 then you could price a single bottle by calculating

1/3

1/6

1/6

4/6 - 1/6 = 3/6 = 1/2

2/3 - 1/6 = ?

C

2 X 2

1

1

3

-

=

=

4

+

1

=

2

2 X 3

6

6

6

6


Multiplying fractions method
Multiplying Fractions - Method £25 then you could price a single bottle by calculating

D


Dividing fractions method
Dividing Fractions - Method £25 then you could price a single bottle by calculating

  • Invert the second fraction and then multiply

D


If it’s £25 then you could price a single bottle by calculating fractionsyou’ve got tosum,

the first thing to do ischeckitsbum.

Add topstogetherif bumsare thesame,

if they’re not, then it’s a pain.

Equal bumsis what youneed,

usetimes tables, yourbumstofeed.

Take awayis thesameasadd,

times and divide are not so bad.

Fortimesdo thebottomandthenthetop,

dividedo thesamewiththe2nd bottom up.


Neilseal method for coverting fpd out of the red and into black

C £25 then you could price a single bottle by calculating

NEILSEAL METHOD FOR COVERTING FPDOUT OF THEREDAND INTO BLACK


. £25 then you could price a single bottle by calculating

How can we write 0.3 as a fraction.

.

Let n = 0.3

.

So 10n = 3.3

.

.

So 10n - n = 3.3 – 0.3

B

So 9n = 3

So n = 3 = 1

9 = 3


. £25 then you could price a single bottle by calculating .

How can we write 0.3451 as a fraction.

..

Let n = 0.3451

..

So 10000n = 3451.451

..

..

So 10000n - 10n = 3451.451 – 3.451

B

So 9990n = 3448

So n = 3448 = 1724

9990 4995


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