Csci 2510 tutorial 1 basic assembly and data representation
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CSCI 2510 Tutorial 1 Basic Assembly and Data Representation. ZONG Wen Department of Computer Science and Engineering The Chinese University of Hong Kong [email protected] Main topic:. 1. Write an assembly program with given instruction 2. Two’s complement operation

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CSCI 2510 Tutorial 1 Basic Assembly and Data Representation

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Csci 2510 tutorial 1 basic assembly and data representation

CSCI 2510 Tutorial 1Basic Assembly and Data Representation

ZONG Wen

Department of Computer Science and Engineering

The Chinese University of Hong [email protected]


Main topic

Main topic:

1. Write an assembly program with given instruction

2. Two’s complement operation

3. Ordering of bytes in data


Write a machine program with given instruction

Write a machine program with given instruction

Basic component of a computer


Write a machine program with given instruction1

Write a machine program with given instruction

There are only 6 machine instructions on a single-accumulator processor, namely:

Load [Memory]{to ACC}e.g. Load [2872]

Store [Memory]{from ACC}e.g. Store [1536]

Add Constant{to ACC}e.g. Add -95

Add [Memory]{to ACC}e.g. Add [2132]

Multiply Constant{to ACC}e.g. Multiply 23

Multiply [Memory]{to ACC}e.g. Multiply [298]


Write a machine program with given instruction2

Write a machine program with given instruction

Variable x and y are stored in address 1000 and 1004, try to implement x2 + y2, store the result in 1008.

Load [1000]; load data to register

Multiply [1000]; perform memory + register operation

Store [1008]; store temporary result to memory

Load[1004];

Multiply[1004];

Add[1008];

Store[1008]; store result


Operation on two s complement

Operation on two’s complement

Example: (–6) + 8 * 3 – 1

Step 1  11111010 + (00001000 * 00000011) – 00000001

Step 2  (11111010 + 00011000) – 00000001

Step 3  00010010 – 00000001

Step 4  00010001

Step 5  17 (decimal answer without overflow)


Operation on two s complement1

Operation on two’s complement

Example: (–6) + 8 * 3 – 1

Step 1  11111010 + (00001000 * 00000011) – 00000001

Step 2  (11111010 + 00011000) – 00000001

Step 3  00010010 – 00000001

Step 4  00010001

Step 5  17 (decimal answer without overflow)


Big endian and little endian

Big endian and little endian

In big endian, you store the most significant byte in the smallest address

In little endian, you store the least significant byte in the smallest address


Big endian and little endian1

Big endian and little endian

For a data of 4 bytes: 90AB12CD

Big endian:


Big endian and little endian2

Big endian and little endian

For a data of 4 bytes: 90AB12CD

Little endian:


Float point representation

Float point representation


Csci 2510 tutorial 1 basic assembly and data representation

Q&A


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