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Factor and Solve: x² - 6x – 27 = 0 4x² - 1 = 0

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Factor and Solve: x² - 6x – 27 = 0 4x² - 1 = 0 - PowerPoint PPT Presentation


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Warm Up. Factor and Solve: x² - 6x – 27 = 0 4x² - 1 = 0 Convert to Vertex Format by Completing the Square (hint: kids at the store) 3. Y = 3x² - 12x + 20. I can write a quadratic equation given solutions from the graph. Identify the 3 forms of a quadratic equation:.

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Presentation Transcript
slide1

Warm Up

Factor and Solve:

  • x² - 6x – 27 = 0
  • 4x² - 1 = 0

Convert to Vertex Format by Completing the Square (hint: kids at the store)

3. Y = 3x² - 12x + 20

identify the 3 forms of a quadratic equation
Identify the 3 forms of a quadratic equation:

Standard Format ax² + bx + c

*** c is where the graph crosses the y axis ***

Vertex Format y = a(x – h)² + k

*** gives the vertex (h, k) ***

Intercept Format y = a(x – p)(x – q)

*** gives the roots, zeros or solutions of the graph ***

slide4
Write a quadratic equation in standard form that has the given solutions and passes through the given point.

Which quadratic format is best to use given the roots of the graph?

INTERCEPT FORM y=a(x – p)(x – q)

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Step 1:

Step 2:

Use the other given point (-4, 3) to find A

3 = a (-4+1)(-4 + 3)

Replace y

With 3

Replace x

With -4

a quadratic equation has roots of 1 3 and passes though 4 3
A quadratic equation has roots of {-1, -3} and passes though (-4, 3).

3 = a (-4+1)(-4 + 3)

Step 3:

Step 4:

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