Objective the student will be able to
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Objective The student will be able to:. solve equations using multiplication and division. Designed by Skip Tyler, Edited by Mr. Nealey. 1) Solve. -5t = 60. To get the variable by itself, which number needs to be moved? -5

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Objective The student will be able to:

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Objective the student will be able to

ObjectiveThe student will be able to:

solve equations using multiplication and division.

Designed by Skip Tyler, Edited by Mr. Nealey


1 solve 5t 60

1) Solve. -5t = 60

To get the variable by itself, which number needs to be moved?

-5

To move the -5, you have to do the opposite operation. What operation will we use?

division


1 solve 5t 601

1) Solve -5t = 60

-5 -5

t = -12

-5(-12) = 60

  • Draw a line to separate the equation into 2 sides

  • Inverse Operations: Divide both sides by -5

  • Simplify

  • Check your answer


2 solve 15 6n

6 6

2.5 = n

15 = 6(2.5)

  • Draw a line.

  • Inverse Operations: Divide both sides by 6

  • Simplify

  • Check your answer

2) Solve 15 = 6n


3 solve 3v 129

Answer Now

3) Solve -3v = -129

  • v = -126

  • v = -43

  • v = 43

  • v = 126


4 solve

4) Solve

You don’t like fractions? Let’s get rid of them! 

“Clear the fraction”

by multiplying both sides of the equation by the denominator.


4 solve1

  • Draw a line

  • Clear the fraction – multiply both sides by 4

  • Simplify

  • Check your answer

4) Solve

4 ·· 4

x = -48


5 solve 18

5) Solve = 18

3 · = 18 · 3

2x = 54

2 2

x = 27

  • Draw a line

  • Clear the fraction – multiply both sides by 3

  • Simplify

  • Inverse Operations: Divide both sides by 2

  • Simplify

  • Check your answer


6 which step clears the fraction in

Answer Now

6) Which step clears the fraction in

  • Multiply by 3

  • Multiply by 5

  • Multiply by -12

  • Multiply by -5


7 solve

Answer Now

7) Solve

  • b = -56

  • b = -14

  • b = 14

  • b = 56


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