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OPEN RESPONSE QUESTION FROM MCAS FALL RETEST 2003, GRADE 10, #17

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INTRODUCTION. OPEN RESPONSE QUESTION FROM MCAS FALL RETEST 2003, GRADE 10, #17.

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OPEN RESPONSE QUESTION FROM MCAS FALL RETEST 2003, GRADE 10, #17

The following is an “Open Response” question for you to practice answering these types of questions in preparation for the State Mandated MCAS. This exercise will help to walk you through the process. There are also some reference links to give you some extra help.

Next

HOW TO ANSWER AN OPEN RESPONSE QUESTION

Be sure to

- Read all parts of each question carefully.
- Make each response as clear, complete and accurate as you can.
- Check all your work!

Next

TOPIC

Apply similarity correspondences (ex. ΔABC ~ ΔXYZ) and properties of the figures to find missing parts of geometric figures, and provide logical justification.

Next

QUESTION #17

To measure the width of a stream indirectly, Claude placed four stakes in the ground at points B, C, D, and E. He used a rock on the opposite bank to determine point A. Triangles ABC and ADE are formed, as shown in the diagram below.

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QUESTION #17

Next

Part A. Explain how you can show BCA is congruent to DEA.

Hint: Separate the diagram into two separate triangles.

Additional

Hint

Next

Part C. Write a proportion or an equation that can be used to determine the distance (indicated by d in the diagram) across the stream.

Hint

Next

Part D. What is the distance across the stream? Show or explain how you obtained your answer.

Hint

Next

REFERENCES

If you are having any trouble with this problem there are some links below that will help you with the standards involved with this question:

http://mathforum.org/dr.math/

http://www.algebra.com/algebra/homework/coordinate/

http://school.discovery.com/homeworkhelp/webmath/

http://www.doe.mass.edu/mcas/

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EVALUATIONThis is the rubric that the state uses to rate responses to question 17. How did you do?

4

The student response demonstrates an exemplary understanding of the Geometry concepts involved in working with similar triangles calculating lengths of sides through proportions.

3

The student response demonstrates a good understanding of the Geometry concepts involved in working with similar triangles calculating lengths of sides through proportions. Although there is significant evidence that the student was able to recognize and apply the concepts involved, some aspect of the response is flawed. As a result the response merits 3 points.

2

The student response contains fair evidence of an understanding of the Geometry concepts involved in working with similar triangles calculating lengths of sides through proportions. While some aspects of the task are completed correctly, others are not. The mixed evidence provided by the student merits 2 points.

1

The student response contains only minimal evidence of an understanding of the Geometry concepts involved in working with similar triangles calculating lengths of sides through proportions.

0

The student response contains insufficient evidence of an understanding of the Geometry concepts involved in working with similar triangles calculating lengths of sides through proportions.

Next

to try another Problem

CONCLUSIONHopefully, this has been a helpful experience for you. The only way to improve is to practice, and there are other problems like this one available for you to try if you are up to the challenge!

-- or --

- Call a friend, have them do the same problem and you can talk about it.

-- or --

- Take a break, you’ve earned it!

Additional Hint for Part A

A

A

d

d + 6 ft

C

B

28 ft

E

D

32 ft

When you separate the two triangles, notice that B and D are congruent and that A is the same angle in each of the two triangles. If you know that two angles of a triangle are congruent to two angles of another triangle, what do you know about the third angle?

Go Back

Hint for Part B

Two triangles are similar if all corresponding angles are congruent and all corresponding sides are in proportion.

In order to prove triangles are similar you must prove one of the following similarities:

SAS

Similarity

SSS

Similarity

AA

Similarity

Back to Part B

A

=

10 ft

20 ft

C

B

10

20

7

14

7 ft

E

D

14 ft

SAS SimilaritySAS Similarity – Prove that two corresponding sides are in proportion and that the corresponding included angles, the angles located in between the sides, are congruent.

Ex.

Since

and B = D = 90 º

then ABC ~ FDE by SAS Similarity.

Back to Hint Page

SSS Similarity

=

=

10

25

8

20

6

15

- SSS Similarity – Prove that all corresponding sides are in proportion.

F

A

Ex.

Since

then ABC ~ FDE by SSS similarity.

10 ft

8 ft

25 ft

20 ft

C

B

6 ft

E

D

15 ft

Back to Hint Page

AA Similarity

F

A

C

65º

B

E

D

65º

AA Similarity – Prove that two corresponding angles are congruent.

Ex.

Since

A = F = 65º

B = D = 90º

then ABC ~ FDE by AA Similarity.

Back to Hint Page

A

=

C

B

E

AB

AD

BC

DE

D

Hint for Part COnce you know the triangles are similar, you can set up a proportion using the sides lengths that are given. In this problem, use

Back to Part C

=

d

d+6

28

32

AB

AD

BC

DE

Hint for Part DSolve the proportion you wrote in part C by cross multiplying:

means that

When you get your solution for d, you will have found the distance across the lake.

Back to Part D

Solution A

- ABC and DEA are congruent because they are both right angles. Angle BAC and DAC are congruent because they are the same angle, reflexive property. There is a theorem that states if two angles of one triangle are congruent to two angles of another triangle, then the third angle is congruent.

As an alternate solution, you could use the sum of the triangles is 180 to explain why the two angles are congruent.

Back to Solution Page

Solution B

Sincefrom part A you know that two angles of one triangle are congruent to two angles of another triangle, then ABE ~ ADE by the AA Similarity Postulate.

Back to Solution Page

=

AB

AD

BC

DE

d

d+6

28

32

Solution CSince you know that:

Plug in the values and write the proportion:

Back to Solution Page

d

d+6

28

32

Solution DFrom part C:

After cross-multiplying:

32d = 28(d+6)

32d = 28d + 168

4d = 168

d = 42

So the distance across the stream, AB, is 42 feet.

Back to Solution Page

I’m done!

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