# Solving A System Of Equations - PowerPoint PPT Presentation

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Solving A System Of Equations. Elida Alvarez &Erika Frias December 19, 2013 5B. Problem Situation. The zoo charges \$4 for every adult and \$2 for every child . Today , the zoo had 272 people in attendance and collected a total of \$664.

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Solving A System Of Equations

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## Solving A System Of Equations

Elida Alvarez &Erika Frias

December 19, 2013

5B

### Problem Situation

The zoo charges \$4 for every adult and \$2 for every child. Today, the zoo had 272 people in attendance and collected a total of \$664.

Find the number of \$4 and \$2 admission fees collected by the zoo today.

### Define Variables

C = number of Children admissions

4A + 2C = 664

A + C = 272

### Solution Method

• We are going to solve this solution by the process of elimination.

### Step 1 of Solution

4A + 2C = 664

• 2A + 2C = 544

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2A = 120

_______ __________

2 2

A = 60

Multiply the second equation by 2 to eliminate the variable C.

### Step 2 of Solution

4(60) + 2C = 664

240 + 2C = 664

-240 = 240

___________________________________

2C = 424

2 2

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C = 212

(60, 212)

### Check of Solution

4(60) + 2(212) = 664

60 + 212 = 272