1 / 6

Chp. 22 RMS and Transformers Sections C & D

Chp. 22 RMS and Transformers Sections C & D. Root Mean Square Current : I rms. rms current is the same as the amount of direct current that would dissipate the same energy in a resistor as is dissipated by the instantaneous alternating current over a complete cycle.

Download Presentation

Chp. 22 RMS and Transformers Sections C & D

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Chp. 22 RMS and TransformersSections C & D

  2. Root Mean Square Current : Irms rms current is the same as the amount of direct current that would dissipate the same energy in a resistor as is dissipated by the instantaneous alternating current over a complete cycle. Irms = ΔVrms R Page. 808 P = (Irms)2 R = ½ (Imax )2 R Irms = Imax = .707 Imax √2 ΔVrms = ΔVmax = .707 ΔVmax √2 *Table 22-2

  3. Transformer Example Diagram

  4. Transformer Equation Page. 815 ΔV2 N1 = N2 ΔV1 ΔV2 = N2 ΔV1 N1 ΔV1 I1 = ΔV2 I2 N= # of turns V = Voltage…potential difference Examples 22 C and 22 D pg 809 and 817

  5. Transformer Problem Ex.

  6. Hmwk #4 Chp. 22 Book (13) • 22C pg. 810 1,3,5 • 22D pg. 818 1,3,5 • Workbook Chp. 22 C & D: • 22C 1. A. Irms = 2000A B. I max = 2800 A C. P= 2.4 x 105 W • 3. I max = 3500A R = 22Ω • 6. ΔV= 25kV • 22D 2. ΔV1 =120V • 4. N= 2000 turns • 3. ΔV2 =.18 V ΔV1 =.0022 V • 7. I 1 = 55 A N= 360 turns

More Related