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Ch. 10 Chemical Quantities. 3 Methods of Measuring. Counting Mass Volume. Example 1. If 0.20 bushel is 1 dozen apples, and a dozen apples has a mass of 2.0 kg, what is the mass of .050 bushel of apples?. Example 1. Count: 1 dozen apples = 12 apples Mass: 1 dozen apples = 2.0 kg apples

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3 methods of measuring
3 Methods of Measuring
  • Counting
  • Mass
  • Volume
example 1
Example 1
  • If 0.20 bushel is 1 dozen apples, and a dozen apples has a mass of 2.0 kg, what is the mass of .050 bushel of apples?
example 11
Example 1
  • Count: 1 dozen apples = 12 apples
  • Mass: 1 dozen apples = 2.0 kg apples
  • Volume: 1 dozen apples = 0.20 bushels

apples

Conversion Factors:

  • 1 dozen2.0 k.g1 dozen

12 apples 1 dozen 0.20 bushels

example 12
Example 1
  • 0.50 bushel x 1 dozen x 2.0 kg =

0.20 bushel 1 dozen

= 5.0 kg

avogadro s number
Avogadro’s Number
  • Named after the Italian scientist Amedo Avogadro di Quaregna
  • 6.02 x 10 23
mole mol
Mole (mol)
  • 1 mol = 6.02 x 10 23 representative particles
  • Representative particles: atoms, molecules ions, or formula units (ionic compound)
mole mol1
Mole (mol)
  • Moles= representative x 1 mol

particles 6.02 x 10 23

example 2 atoms mol
Example 2 (atoms  mol)
  • How many moles is 2.80 x 10 24 atoms of silicon?
example 2
Example 2
  • 2.80 x 10 24 atoms Si x 1 mol Si

6.02 x 10 23 atoms Si

= 4.65 mol Si

example 3 mol molecule
Example 3 (mol  molecule)
  • How many molecules of water is 0.360 moles?
example 3
Example 3
  • 0.360 mol H2O x 6.02 x 10 23 molecules H2O 1 mol H2O

=2.17 molecules H2O

the mass of a mole of an element
The Mass of a Mole of an Element
  • The atomic mass of an element expressed in grams = 1 mol of that element = molar mass

Molar mass S

Molar mass Hg

Molar mass C

Molar mass Fe

slide14

6.02 x 10 23 atoms S

6.02 x 10 23 atoms Hg

6.02 x 10 23 atoms C

6.02 x 10 23 atoms Fe

example 4 mol gram
Example 4 (mol  gram)
  • If you have 4.5 mols of sodium, how much does it weigh?
example 4
Example 4
  • .45 mol Na x 23 g Na = 10.35 g Na = 1.0 x 10 2 g Na

1 mol Na

example 5 grams atoms
Example 5 (grams  atoms)
  • If you have 34.3 g of Iron, how many atoms are present?
example 5
Example 5
  • 34.3 g Fe x 1 mol Fe x 6.02 x 10 23 atoms

55.8 g Fe 1 mol Fe

=3.70 x 10 23 atoms Fe

the mass of a mole of a compound
The Mass of a Mole of a Compound
  • To find the mass of a mole of a compound you must know the formula of the compound
  • H2O  H= 1 g x 2

O= 16 g

18 g = 1 mole = 6.02 x 10 23

molecules

example 6 gram mol
Example 6 (gram  mol)
  • What is the mass of 1 mole of sodium hydrogen carbonate?
example 6
Example 6
  • Sodium Hydrogen Carbonate = NaHCO3
  • Na=23 g
  • H=1 g
  • C=12 g
  • O=16 g x3
  • 84 g NaHCO3 = 1 mol NaHCO3
mole volume relationship
Mole-Volume Relationship
  • Unlike liquids and solids the volumes of moles of gases at the same temperature and pressure will be identical
avogadro s hypothesis
Avogadro’s Hypothesis
  • States that equal volumes of gases at the same temperature and pressure contain the same number of particles
  • Even though the particles of different gases are not the same size, since the gas particles are spread out so far the size difference is negligible
standard temperature and pressure stp
Standard Temperature and Pressure (STP)
  • Volume of a gas changes depending on temperature and pressure
  • STP= 0oC (273 K)

101.3 kPa (1 atm)

standard temperature and pressure stp1
Standard Temperature and Pressure (STP)
  • At STP, 1 mol = 6.02 X 1023 particles = 22.4 L of ANY gas= molar volume
conversion factors
Conversion Factors
  • AT STP
  • 1 mol gas22.4 L gas

22.4 L gas 1 mol gas

example 7
Example 7
  • At STP, what volume does 1.25 mol He occupy?
example 71
Example 7
  • 1.25 mol He x 22.4 L He = 28.0 L He

1 mol He

example 8
Example 8
  • If a tank contains 100. L of O2 gas, how many moles are present?
example 81
Example 8
  • 100. L O2 X 1 mol O2 = 4.46 mol O2

22.4 L O2

calculating molar mass from density
Calculating Molar Mass from Density
  • The density of a gas at STP is measured in g/L
  • This value can be sued to determine the molar mass of gas present
example 9
Example 9
  • A gaseous compound of sulfur and oxygen has a density of 3.58 g/L at STP. Calculate the molar mass.
example 91
Example 9
  • 1 mol gas x 22.4 L gas X 3.58 g gas =

1 mol gas 1 L gas

Molar Mass= 80.2 g

percent composition
Percent Composition
  • The relative amounts of the elements in a compound
  • These percentages must equal 100
percent composition1
Percent Composition
  • %element = mass of element x 100

mass of compound

example 10
Example 10
  • Find the percentage of each element present in Al2 (CO3)3
example 101
Example 10
  • Al2(CO3)3
  • Al= 27 g x 2 = 54 g / 234 g x 100=23%
  • C= 12 g x 3 = 36 g/ 234 g x 100= 15%
  • O = 16 g x 9 = 144 g / 234 g x 100=62%

234 gAl2(CO3)3

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