5.2 Perpendicular and Angle Bisectors

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# 5.2 Perpendicular and Angle Bisectors - PowerPoint PPT Presentation

5.2 Perpendicular and Angle Bisectors. A point is equidistant from two objects if it is the same distance from the objects. Perpendicular Bisector Theorem. If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

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## PowerPoint Slideshow about ' 5.2 Perpendicular and Angle Bisectors' - aladdin-horton

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Presentation Transcript
5.2 Perpendicular and Angle Bisectors
• A point is equidistant from two objects if it is the same distance from the objects.
Perpendicular Bisector Theorem
• If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
Converse of the Perpendicular Bisector Theorem
• If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.
Using the Perpendicular Bisector Theorem
• What is the length of segment AB?

BA = BC

4x = 6x – 10

-2x = -10

x = 5

AB = 4x

AB = 4 (5)

AB = 20

Distance from a Point to a Line
• The distance from a point to a line is the length of the perpendicular segment from the point to the line.
• Is also the length of the shortest segment from the point to the line.
Angle Bisector Theorem
• If a point is on the bisector of an angle, then the point is equidistant from the sides of the angle.
Converse of the Angle Bisector Theorem
• If a point in the interior of an angle is equidistant from the sides of the angle, then the point is on the angle bisector.
Using the Angle Bisector Theorem
• What is the length of segment RM?

RM = RP

7x = 2x + 25

5x = 25

x = 5

RM = 7x

RM = 7 (5)

RM = 35

More Practice!!!!!
• Homework – Textbook p. 296 – 297 #6 – 22.