1 / 12

To specify a Riemann sum, we choose a partition and a set of sample points.

adelie
Download Presentation

To specify a Riemann sum, we choose a partition and a set of sample points.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Recall that RN, LN, and MN use rectangles of equal width Δx, whose heights are the values of f (x) at the endpoints or midpoints of the subintervals. In Riemann sum approximations, we relax these requirements: The rectangles need not have equal width, and the height may be any value of f (x) within the subinterval.

  2. To specify a Riemann sum, we choose a partition and a set of sample points. • PartitionP of size N: a choice of points that divides [a, b] into N subintervals. • P: a = x0 < x1 < x2 <…< xN = b • Sample pointsC = {c1,…, cN}: • cibelongs to the subinterval [xi−1, xi] for all i.

  3. The norm of P, denoted , is the maximum of the lengths Δxi. Given P and C, we construct the rectangle of height f (ci) and base Δxi over each subinterval [xi−1, xi]. This rectangle has area f (ci)Δxi if f (ci) ≥ 0. If f (ci) < 0, the rectangle extends below the x-axis, and f (ci)Δxi is the negative of its area. The Riemann sum is the sum

  4. Calculate R (f, P, C), where f (x) = 8 + 12 sin x − 4x on [0, 4], P : x0 = 0 < x1 = 1 < x2 = 1.8 < x3 = 2.9 < x4 = 4 C = {0.4, 1.2, 2, 3.5} What is the norm ?

  5. DEFINITION Definite Integral The definite integral of f (x) over [a, b], denoted by the integral sign, is the limit of Riemann sums: When this limit exists, we say that f (x) is integrable over [a, b].

  6. One of the greatest mathematicians of the nineteenth century and perhaps second only to his teacher C. F. Gauss, Riemann transformed the fields of geometry, analysis, and number theory. Albert Einstein based his General Theory of Relativity on Riemann’s geometry. The “Riemann hypothesis” dealing with prime numbers is one of the great unsolved problems in present-day mathematics. The Clay Foundation has offered a $1 million prize for its solution (http://www.claymath.org/millennium).

  7. CONCEPTUAL INSIGHT Keep in mind that a Riemann sum R (f, P, C) is nothing more than an approximation to area based on rectangles, and that            is the number we obtain in the limit as we take thinner and thinner rectangles. However, general Riemann sums (with arbitrary partitions and sample points) are rarely used for computations. In practice, we use particular approximations such as MN, or the Fundamental Theorem of Calculus, as we’ll learn in the next section. If so, why bother introducing Riemann sums? The answer is that Riemann sums play a theoretical rather than a computational role. They are useful in proofs and for dealing rigorously with certain discontinuous functions. In later sections, Riemann sums are used to show that volumes and other quantities can be expressed as definite integrals

  8. The next theorem assures us that continuous functions (and even functions with finitely many jump discontinuities) are integrable. In practice, we rely on this theorem rather than attempting to prove directly that a given function is integrable. THEOREM 1If f (x) is continuous on [a, b], or if f (x) is continuous with at most finitely many jump discontinuities, then f (x) is integrable over [a, b].

  9. DEFINITION Reversing the Limits of Integration For a < b, we set

More Related