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example 3

example 3. Loan Balance. Chapter 1.3.

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example 3

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  1. example 3 Loan Balance Chapter 1.3 A business property is purchased with a promise to pay off a $60,000 loan plus the $16,500 interest on this loan by making 60 monthly payments of $1275. The amount of money, y, remaining to be paid on $76,500 (the loan plus interest) is reduced by $1275 each month. Although the amount of money remaining to be paid changes every month, it can be modeled by the linear function where x is the number of monthly payments made. We recognize that only integer values of x from 0 to 60 apply to this application. Find the x-intercept and the y-intercept of the graph of this linear function. Interpret the intercepts in the context of this problem situation. How should x and y be limited in this model so that they make sense in the application? Use the intercepts and the results of part (c) to sketch the graph of the given equation. 2009 PBLPathways

  2. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  3. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  4. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  5. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  6. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  7. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  8. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  9. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  10. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  11. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  12. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  13. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  14. Money remaining to be paid Number of monthly payments made Find the x-intercept and the y-intercept of the graph of this linear function. x-intercepts: set y = 0 y-intercept: set x = 0 (0, 76500) (60, 0)

  15. Money remaining to be paid Number of monthly payments made Interpret the intercepts in the context of this problem situation. (60, 0) When x = 60, the values of y = 0. “The loan is paid off in 60 months”. (0, 76500) When x = 0, the values of y = 76,500. “A total of $76,500 must be repaid”.

  16. Money remaining to be paid Number of monthly payments made Interpret the intercepts in the context of this problem situation. (60, 0) When x = 60, the values of y = 0. “The loan is paid off in 60 months”. (0, 76500) When x = 0, the values of y = 76,500. “A total of $76,500 must be repaid”.

  17. Money remaining to be paid Number of monthly payments made Interpret the intercepts in the context of this problem situation. (60, 0) When x = 60, the values of y = 0. “The loan is paid off in 60 months”. (0, 76500) When x = 0, the values of y = 76,500. “A total of $76,500 must be repaid”.

  18. Money remaining to be paid Number of monthly payments made Interpret the intercepts in the context of this problem situation. (60, 0) When x = 60, the values of y = 0. “The loan is paid off in 60 months”. (0, 76500) When x = 0, the values of y = 76,500. “A total of $76,500 must be repaid”.

  19. Money remaining to be paid Number of monthly payments made Interpret the intercepts in the context of this problem situation. (60, 0) When x = 60, the values of y = 0. “The loan is paid off in 60 months”. (0, 76500) When x = 0, the values of y = 76,500. “A total of $76,500 must be repaid”.

  20. Money remaining to be paid Number of monthly payments made How should x and y be limited in this model so that they make sense in the application? Number of monthly payments made Payments most be integers from 0 to 60. Money remaining to be paid Money remaining to paid is from 0 to $76,500.

  21. Money remaining to be paid Number of monthly payments made How should x and y be limited in this model so that they make sense in the application? Number of monthly payments made Payments most be integers from 0 to 60. Money remaining to be paid Money remaining to paid is from 0 to $76,500.

  22. Money remaining to be paid Number of monthly payments made How should x and y be limited in this model so that they make sense in the application? Number of monthly payments made Payments must be integers from 0 to 60. Money remaining to be paid Money remaining to paid is from 0 to $76,500.

  23. Money remaining to be paid Number of monthly payments made How should x and y be limited in this model so that they make sense in the application? Number of monthly payments made Payments must be integers from 0 to 60. Money remaining to be paid Money remaining to be paid is from 0 to $76,500.

  24. Money remaining to be paid Number of monthly payments made Use the intercepts and the results of part (c) to sketch the graph of the given equation.

  25. Money remaining to be paid Number of monthly payments made Use the intercepts and the results of part (c) to sketch the graph of the given equation. y x

  26. Money remaining to be paid Number of monthly payments made Use the intercepts and the results of part (c) to sketch the graph of the given equation. y The vertical axis has to include values from 0 to 76,500. x

  27. Money remaining to be paid Number of monthly payments made Use the intercepts and the results of part (c) to sketch the graph of the given equation. y x The horizontal axis has to include values from 0 to 60.

  28. Money remaining to be paid Number of monthly payments made Use the intercepts and the results of part (c) to sketch the graph of the given equation. y x

  29. Money remaining to be paid Number of monthly payments made Use the intercepts and the results of part (c) to sketch the graph of the given equation. y x

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