Sec 3.3 Angle Addition Postulate &amp; Angle Bisector

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# Sec 3.3 Angle Addition Postulate & Angle Bisector - PowerPoint PPT Presentation

Sec 3.3 Angle Addition Postulate &amp; Angle Bisector. Objective: What we’ll learn…. Find the measure of an angle by using Angle Addition Postulate . Find the measure of an angle by using definition of Angle Bisector. Angle Addition Postulate.

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Presentation Transcript
Objective: What we’ll learn…
• Find the measure of an angle by using Angle Addition Postulate.
• Find the measure of an angle by using definition of Angle Bisector.

First, let’s recall some previous information from last week….

We discussed the Segment Addition Postulate, which stated that we could add the lengths of adjacent segments together to get the length of an entire segment.

For example:

JK + KL = JL

If you know that JK = 7 and KL = 4, then you can conclude that JL = 11.

The Angle Addition Postulate is very similar, yet applies to angles. It allows us to add the measures of adjacent angles together to find the measure of a bigger angle…

J

K

L

If Q is between P and R, then

PQ + QR = PR.

If PQ +QR = PR, then Q is between P and R.

2x

4x + 6

R

P

Q

PQ = 2x QR = 4x + 6 PR = 60

Use the Segment Addition Postulate find the measure of PQ and QR.

Step 1:

PQ + QR = PR (Segment Addition)

2x + 4x + 6 = 60

6x + 6 = 60

6x = 54

x =9

PQ = 2x = 2(9) = 18

QR =4x + 6 = 4(9) + 6 = 42

Step 2:

Step 3:

Step 4:

Steps
• Draw and label the Line Segment.
• Set up the Segment Addition/Congruence Postulate.
• Set up/Solve equation.
• Calculate each of the line segments.

Slide 2

If B lies on the interior of ÐAOC,

then mÐAOB + mÐBOC = mÐAOC.

B

A

mÐAOC = 115°

50°

C

65°

O

D

Example 1:

Example 2:

Slide 3

G

114°

K

134°

46°

A

B

C

95°

19°

This is a special example, because the two adjacent angles together create a straight angle.

Predict what mÐABD + mÐDBC equals.

ÐABC is a straight angle, therefore mÐABC = 180.

mÐABD + mÐDBC = mÐABC

mÐABD + mÐDBC = 180

So, if mÐABD = 134,

then mÐDBC = ______

H

J

Given: mÐGHK = 95

mÐGHJ = 114.

Find: mÐKHJ.

The Angle Addition Postulate tells us:

mÐGHK + mÐKHJ = mÐGHJ

95 + mÐKHJ = 114

mÐKHJ = 19.

Plug in what you know.

46

Solve.

Given:

mÐRSV = x + 5

mÐVST = 3x - 9

mÐRST = 68

Find x.

Algebra Connection

Slide 4

R

V

Extension: Now that you know x = 18, find mÐRSV and mÐVST.

mÐRSV = x + 5

mÐRSV = 18 + 5 = 23

mÐVST = 3x - 9

mÐVST = 3(18) – 9 = 45

Check:

mÐRSV + mÐVST = mÐRST

23+ 45 =68

S

T

Set up an equation using the Angle Addition Postulate.

mÐRSV + mÐVST = mÐRST

x + 5 + 3x – 9= 68

4x- 4 = 68

4x = 72

x = 18

Plug in what you know.

Solve.

mÐBQC = x – 7 mÐCQD = 2x – 1 mÐBQD = 2x + 34

Find x, mÐBQC, mÐCQD, mÐBQD.

C

B

mÐBQC = x – 7

mÐBQC = 42 – 7 = 35

mÐCQD = 2x – 1

mÐCQD = 2(42) – 1 = 83

mÐBQD = 2x + 34

mÐBQD = 2(42) + 34 = 118

Check:

mÐBQC + mÐCQD = mÐBQD

35+83 = 118

Q

D

mÐBQC + mÐCQD = mÐBQD

x – 7 + 2x – 1 = 2x + 34

3x – 8 = 2x + 34

x – 8 = 34

x = 42

x = 42

mÐCQD = 83

Algebra Connection

Slide 5

mÐBQC = 35

mÐBQD = 118

o

ALGEBRAGiven that m LKN =145 , find m LKM andm MKN.

So, m LKM = 56°and m MKN = 89°.

Animated Solution

EXAMPLE 3

Find angle measures

o

ALGEBRAGiven that m LKN =145 , find m LKM andm MKN.

So, m LKM = 56°and m MKN = 89°.

Animated Solution

EXAMPLE 3

Find angle measures

o

ALGEBRAGiven that m LKN =145 , find m LKM andm MKN.

So, m LKM = 56°and m MKN = 89°.

Animated Solution

EXAMPLE 3

Find angle measures

Find the indicated angle measures.

3. Given that KLMis a straight angle, find mKLN andm NLM.

125°, 55°

for Example 3

GUIDED PRACTICE

60°, 30°

for Example 3

GUIDED PRACTICE

T and S, P and R.

m T = 121°,

m P = 84°

Congruent Angles

Two angles are congruent if they have the same measure.

Congruent angles in a diagram are marked by matching arcs at the vertices .

Identify all pairs of congruent angles in the diagram.

In the diagram, m∠Q = 130° , m∠R = 84°, and m∠ S = 121° . Find the other angle measures in the diagram.

o

m XYZ = m XYW + m WYZ = 18° + 18° = 36°.

Angle Bisecotrs

An angle bisector is a ray that divides an angle into two congruent angles.

o

ALGEBRAGiven that m LKN =145 , find m LKM andm MKN.

STEP 1

Write and solve an equation to find the value of x.

mLKN = m LKM + mMKN

o

o

o

145 = (2x + 10)+ (4x – 3)

EXAMPLE 3

Animated Solution – Click to see steps and reasons.

SOLUTION

Substitute angle measures.

145 = 6x + 7

Combine like terms.

138 = 6x

Subtract 7 from each side.

23 = x

Divide each side by 6.

STEP 2

Evaluate the given expressions when x = 23.

mLKM = (2x+ 10)° = (2 23+ 10)° = 56°

mMKN = (4x– 3)° = (4 23– 3)° = 89°

So, m LKM = 56°and m MKN = 89°.

EXAMPLE 3

Find angle measures

Back to Notes.

3.3 Angle Bisector
• A ray that divides an angle into 2 congruent adjacent angles.

BD is an angle bisector. bisector of <ABC.

A

D

B

C

Example 1

SOLUTION

mABD

BDbisects ABC.

=

Simplify.

Find Angle Measures

BD bisectsABC, andmABC = 110°.

Find mABDand mDBC.

1

1

2

2

(mABC)

Substitute110°formABC.

=

(110°)

=

55°

ABD andDBCare congruent, somDBC= mABD.

So, mABD = 55°, and mDBC = 55°.

Example 2

MP

bisectsLMN, andmLMP =46°.

b.

Determine whether LMN is acute, right, obtuse,

or straight. Explain.

SOLUTION

a.

MP

bisectsLMN, somLMP = mPMN .

b.

LMN is obtuse because its measure is between 90° and 180°.

Find Angle Measures and Classify an Angle

a.

Find mPMNandmLMN.

You know thatmLMP = 46°. Therefore, mPMN = 46°.

The measure ofLMN is twice the measure of LMP.

mLMN =2(mLMP) = 2(46°) = 92°

So, mPMN = 46°, andmLMN = 92°

Checkpoint

HK bisects GHJ. Find mGHK and mKHJ.

26°; 26°

80.5°; 80.5°

45°; 45°

Find Angle Measures

1.

2.

3.

Checkpoint

QSbisects PQR. Find mSQPand mPQR. Then determine whether PQRis acute, right, obtuse, or straight.

29°; 58°; acute

45°; 90°; right

60°; 120°; obtuse

Find Angle Measures and Classify an Angle

4.

5.

6.

Example 3

SOLUTION

mDAB

=

2(mABC)

ACbisects DAB.

Substitute45°formBAC.

mBCD

=

CAbisects BCD.

Real Life

In the kite, DAB is bisected AC,and BCD is bisected by CA.Find mDAB and mBCD.

2(mACB)

Simplify.

2(45°)

=

=

2(27°)

=

=

90°

54°

Substitute27°formACB.

Simplify.

The measure of DABis 90°, and the measure of BCDis 54°.

Checkpoint

7.

KM bisects JKL.

Find mJKM and mMKL.

48°; 48°

60°; 120°

8.

UVbisects WUT.

Find mWUVand mWUT.

Real Life

• Using the vertex O as a center, draw an arc to meet the arms of the angle (at X and Y).
• Using X as a center and the same radius, draw a new arc.
• Using Y as center and the same radius, draw an overlapping arc.
• Mark the point where the arcs meet.
• The bisector is the line from O to this point.

A

X

E

O

Y

B

Solve for x.

* If they are congruent, set them equal to each other, then solve!

x+40o

x+40=3x-20

40=2x-20

60=2x

30=x

3x-20o

Example 4

RQ bisects PRS.Find the value of x.

RQbisects PRS.

Use Algebra with Angle Measures

SOLUTION

mQRS

Substitute givenmeasures.

(6x + 1)°

Subtract 1 from each side.

mPRQ

=

6x = 84

6x + 1 – 1

Simplify.

85°

=

Divide each side by 6.

=

85 – 1

6x

84

––

––

Simplify.

x = 14

=

6

6

CHECK

for x.

mPRQ = (6x + 1)° = (6 · 14 + 1)° = (84 + 1)° = 85°

Checkpoint

BD bisects ABC. Find the value of x.

43

3

Use Algebra with Angle Measures

55 = x + 12

X =43

9.

9x = 8x + 3

x = 3

10.