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This PowerPoint is designed to help with your Multiple Regression homework

This PowerPoint is designed to help with your Multiple Regression homework. It will work best if played (rather than just printed) so you can view the animations. We will also review this homework assignment in class. 4.0 3.0 2.0 1.0. 4.0 3.0 2.0 1.0. 4.0 3.0 2.0 1.0. GPA. GPA.

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This PowerPoint is designed to help with your Multiple Regression homework

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  1. This PowerPoint is designed to help with your Multiple Regression homework It will work best if played (rather than just printed) so you can view the animations We will also review this homework assignment in class

  2. 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 GPA GPA GPA 0 200 300 400 500 600 0 1 2 3 4 0 200 300 400 500 600 High School GPA SAT (Verbal) SAT (Mathematical) r(7) = 0.50 r(7) = + 0.80 r(7) = + 0.80 r(7) = + 0.911444123 r(7) = + 0.616334867 r(7) = + 0.487295007

  3. 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 GPA GPA GPA 0 200 300 400 500 600 0 1 2 3 4 0 200 300 400 500 600 High School GPA SAT (Verbal) SAT (Mathematical) r(7) = 0.50 r(7) = + 0.80 r(7) = + 0.80 r(7) = + 0.911444123 r(7) = + 0.616334867 r(7) = + 0.487295007

  4. 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 GPA GPA GPA 0 200 300 400 500 600 0 1 2 3 4 0 200 300 400 500 600 High School GPA SAT (Verbal) SAT (Mathematical) r(7) = 0.50 r(7) = + 0.80 r(7) = + 0.80 r(7) = + 0.911444123 r(7) = + 0.616334867 r(7) = + 0.487295007

  5. 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 4.0 3.0 2.0 1.0 GPA GPA GPA 0 200 300 400 500 600 0 1 2 3 4 0 200 300 400 500 600 High School GPA SAT (Verbal) SAT (Mathematical) r(7) = 0.50 r(7) = + 0.80 r(7) = + 0.80 r(7) = + 0.911444123 r(7) = + 0.616334867 r(7) = + 0.487295007

  6. No - 0 .41107

  7. No - 0 .41107 Yes + 1.2013

  8. No - 0 .41107 Yes + 1.2013 No 0.0016

  9. No - 0 .41107 Yes + 1.2013 No 0.0016 No - 0 .0019

  10. No - 0 .41107 Yes + 1.2013 No 0.0016 No - 0 .0019 High School GPA

  11. No - 0 .41107 Yes + 1.2013 No 0.0016 No - 0 .0019 High School GPA + 1.2013x1 + 0 .0016 x2 Y’ = - 0 .41107 - 0 .0019 x3

  12. 1.201 .0016 .0019 + 1.2013x1 + 0 .0016 x2 Y’ = - 0 .41107 - 0 .0019 x3 + 1.2013(2.8) = 2.76 2.76 + 0.0016 (430) Y’ = - 0 .411 - 0 .0019 (460)

  13. 1.201 .0016 .0019 + 1.2013x1 + 0 .0016 x2 Y’ = - 0 .41107 - 0 .0019 x3 + 1.2013(3.8) = 3.96 3.96 + 0 .0016 (430) Y’ = - 0 .411 - 0 .0019 (460)

  14. 1.201 .0016 .0019 2.76 3.96 = 1.8016 3.96 - 2.76 = 1.2 Yes, use the regression coefficient for the HS GPA (1.2), to estimate the change

  15. This second part of the PowerPoint tutorial is designed to help review the Multiple Regression problem completed in lab It will work best if played (rather than just printed) so you can view the animations

  16. 500 400 300 200 100 500 400 300 200 100 500 400 300 200 100 Heating Cost Heating Cost Heating Cost 0 20 40 60 80 0 20 40 60 80 0 20 40 60 80 Average Temperature Insulation Age of Furnace r(18) = - 0.50 r(18) = - 0.40 r(18) = + 0.60 r(18) = - 0.811508835 r(18) = - 0.257101335 r(18) = + 0.536727562

  17. 500 400 300 200 100 500 400 300 200 100 500 400 300 200 100 Heating Cost Heating Cost Heating Cost 0 20 40 60 80 0 20 40 60 80 0 20 40 60 80 Average Temperature Insulation Age of Furnace r(18) = - 0.50 r(18) = - 0.40 r(18) = + 0.60 r(18) = - 0.811508835 r(18) = - 0.257101335 r(18) = + 0.536727562

  18. + 427.19 - 4.5827 -14.8308 + 6.1010 - 4.5827 x1 - 14.8308 x2 427.19 + 6.1010 x3 Y’ =

  19. + 427.19 - 4.5827 -14.8308 + 6.1010 - 4.5827 x1 - 14.8308 x2 427.19 + 6.1010 x3 Y’ =

  20. + 427.19 - 4.5827 -14.8308 + 6.1010 - 4.5827 x1 - 14.8308 x2 427.19 + 6.1010 x3 Y’ =

  21. + 427.19 - 4.5827 -14.8308 + 6.1010 - 4.5827 x1 - 14.8308 x2 427.19 + 6.1010 x3 Y’ =

  22. + 427.19 - 4.5827 -14.8308 + 6.1010 - 4.5827 x1 - 14.8308 x2 427.19 + 6.1010 x3 Y’ =

  23. 4.58 14.83 6.10 - 4.5827(30) +6.1010 (10) -14.8308 (5) 427.19 Y’ = + 61.010 - 74.154 - 137.481 = $ 276.56 = $ 276.56 427.19 Y’ = Calculate the predicted heating cost using the new value for the age of the furnace Use the regression coefficient for the furnace ($6.10), to estimate the change

  24. 4.58 14.83 6.10 - 4.5827(30) +6.1010 (10) -14.8308 (5) 427.19 Y’ = + 61.010 - 74.154 - 137.481 = $ 276.56 427.19 Y’ = - 4.5827(30) +6.1010 (10) -14.8308 (5) 427.19 Y’ = These differ by only one year but heating cost changed by $6.10 282.66 – 276.56 = 6.10 + 61.010 - 74.154 - 137.481 = $ 276.56 = $ 276.56 427.19 Y’ = $ 276.56 - 4.5827(30) +6.1010 (11) -14.8308 (5) 427.19 Y’ = + 67.111 - 74.154 - 137.481 = $ 282.66 427.19 Y’ = Calculate the predicted heating cost using the new value for the age of the furnace Use the regression coefficient for the furnace ($6.10), to estimate the change

  25. Thank you! Good luck with your studies!

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