Charles's Law. The relationship between temperature and volume. How Volume Varies With Temperature . If we place a balloon in liquid nitrogen it shrinks:. So, gases shrink if cooled. Conversely, if we heat a gas it expands (as in a hot air balloon).
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The relationship between temperature and volume
If we place a balloon in liquid nitrogen it shrinks:
So, gases shrink if cooled.
Conversely, if we heat a gas it expands (as in a hot air balloon).
Let’s take a closer look at temperature before we try to find the exact relationship of V vs. T.
Is 20C twice as hot as 10C?
Is 20 kg twice as heavy as 10 kg?Temperature scales
No. 68F (20C) is not double 50F (10C)
Yes. 44 lb (20 kg) is double 22 lb (10 kg)
What’s the difference?
Temperature (C)Temperature vs. Volume Graph (fig.7,8 pg.430)
25 mL at 22C
31.6 mL, 23.1 mL
Y=0.0847x + 23.137
62C = ? K: K=C+273 = 62 + 273 = 335 K
Absolute zero is –273C or 0 K
What is the approximate temperature for absolute zero in degrees Celsius and kelvin?
Calculate the missing temperatures
0C = _______ K 100C = _______ K
100 K = _______ C –30C = _______ K
300 K = _______ C 403 K = _______ C
25C = _______ K 0 K = _______ C
Read pages 432-3. Answer these questions:
Charles’s Law: as the temperature of a gas increases, the volume increases proportionally, provided that the pressure and amount of gas remain constant,
V1/T1 = V2/T2
V1 = 3.5 L, T1 = 300K, V2 = ?, T2 = 200K
Using Charles’ law: V1/T1 = V2/T2
3.5 L / 300 K = V2 / 200 K
V2 = (3.5 L/300 K) x (200 K) = 2.3 L
V1 = 1 L, T1 = 22°C = 295 K
V2 = ?, T2 = 100 °C = 373 K
V1/T1 = V2/T2,1 L / 295 K = V2 / 373 K
V2 = (1 L/295 K) x (373 K) = 1.26 L
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